Opening serial port feedback

[SaeedAID]

Dear Geoffrey

Before getting to the issue I would like to thank you for your well-written code and your effort.

Well I would like you to help me to have a better understanding of a scenario that could happen, imagine the port we are trying to open is not available or disconnected, there is no feedback on the opening port so the code would crash and stop.

Can we catch the error or does the code returns an integer or boolean on the port opening so we can check it? This could help us with diagnostic errors so we put it on the while loop until the port became available.

Best regards

Saeed

[gbmhunter]

Hi @SaeedAID , I believe it throws an exception if it can't open the /dev/ttyXXX "file" for read/write access as per this screenshot of the code.

The exception is of the following type:

You should be cable to try/catch the exception to do appropriate error handling. Let me know if this does not suit your needs.

[SaeedAID]

Dear Geoffrey

Thank you for your quick reply, yes I have seen that and unfortunately, I couldn't add it to my code. Can you please advise Mr on how to implement on my code or provide me an example code please

[gbmhunter]

Hi @SaeedAID , I think you want something like this (haven't been able to test it sorry!):

#include <CppLinuxSerial/Exception.hpp>

int main() {
  // Setup goes here
  try {
    mySerialPort.Read(data);
  } catch (mn::CppLinuxSerial::Exception e) {
    std::cout << "Error occurred while reading!" << std::endl;
  }
  // ...
}