Cleanup Scripts | Add 06.11.2025.sql

Author: karkessler

Vorlesung/Übungen/06_11_2025.sql

@@ -0,0 +1,77 @@
+-- Relationale Division
+
+USE 25_26;
+
+DROP TABLE IF EXISTS Kunde;
+DROP TABLE IF EXISTS Produkt;
+
+CREATE TABLE Kunde (
+  Kunde VARCHAR(50),
+  Produkt VARCHAR(50)
+);
+
+INSERT INTO Kunde (Kunde, Produkt) VALUES
+('Alice', 'Laptop'),
+('Alice', 'Smartphone'),
+('Bob', 'Laptop'),
+('Bob', 'Tablet'),
+('Carol', 'Laptop'),
+('Carol', 'Smartphone'),
+('Carol', 'Tablet');
+
+CREATE TABLE Produkt (
+  Produkt VARCHAR(50)
+);
+
+INSERT INTO Produkt (Produkt) VALUES
+('Laptop'),
+('Smartphone');
+
+SELECT DISTINCT K1.Kunde as Kunde_1
+FROM Kunde AS K1
+WHERE NOT EXISTS (
+    SELECT Produkt.Produkt
+    FROM Produkt
+    WHERE NOT EXISTS (
+        SELECT 1
+        FROM Kunde AS K2
+        WHERE K2.Kunde = K1.Kunde
+          AND K2.Produkt = Produkt.Produkt
+    )
+);
+
+WITH
+-- π_Kunde(B)
+kunden AS (
+  SELECT DISTINCT Kunde FROM Kunde
+),
+
+-- (π_Kunde(B) × P)   -- kartesisches Produkt
+soll AS (
+  SELECT k.Kunde, p.Produkt
+  FROM kunden k
+  CROSS JOIN Produkt p
+),
+
+-- (π_Kunde(B) × P) − B
+fehlend AS (
+  SELECT Kunde, Produkt FROM soll
+  EXCEPT
+  SELECT Kunde, Produkt FROM Kunde
+),
+
+-- π_Kunde( fehlend )   -- Kunden, denen etwas fehlt
+fehlerkunden AS (
+  SELECT DISTINCT Kunde FROM fehlend
+),
+
+-- π_Kunde(B) − π_Kunde( fehlend )
+ergebnis AS (
+  SELECT Kunde FROM kunden
+  EXCEPT
+  SELECT Kunde FROM fehlerkunden
+)
+SELECT * FROM ergebnis
+ORDER BY Kunde;
+
+

Vorlesung/Übungen/23_10_2025.sql

@@ -1,18 +1,17 @@
+-- Verschiedene Übungen zu den Vorlesungen
+
 USE 25_26;
 
 DROP TABLE IF EXISTS Hoeren;
-
-
 DROP TABLE IF EXISTS Vorlesung;
 DROP TABLE IF EXISTS Assistent;
 DROP TABLE IF EXISTS Professor;
 DROP TABLE IF EXISTS Doktorand;
 DROP TABLE IF EXISTS Angestellter;
 DROP TABLE IF EXISTS Fahrzeughalter;
 DROP TABLE IF EXISTS Student;
-
 DROP TABLE IF EXISTS Auto;
-drop table IF EXISTS senior;
+drop table IF EXISTS Senior;
 DROP TABLE IF EXISTS Hochschule;
 
 CREATE TABLE Hochschule
@@ -64,8 +63,6 @@ VALUES (3,'Meier', 4, 22);
 INSERT INTO Student (MatNr, Name, Semester, HS)
 VALUES (4,'Meier', 4, 33);
 
-
-
 SELECT * FROM Student;
 SELECT * FROM Hochschule;
 SELECT * FROM Vorlesung;

Vorlesung/Übungen/Datenbanken4Übungen_2.sql

@@ -1,23 +1,21 @@
 -- -----------------------------------------------
--- - Szenario 2: c-c:
 -- - 1. Männer sind mit Frauen verheiratet oder nicht.
 -- - 2. Männer und Frauen können nur einmal gleichzeitig verheiratet sein
 -- -----------------------------------------------
 
 USE 25_26;
 
 DROP TABLE IF EXISTS Ehepaar;
-DROP TABLE IF EXISTS Männer;
-DROP TABLE IF EXISTS Frauen;;
-
+DROP TABLE IF EXISTS Mann;
+DROP TABLE IF EXISTS Frau;;
 
 -- -----------------------------------------------
-CREATE TABLE Männer 
+CREATE TABLE Mann
 (MaNr INTEGER NOT NULL PRIMARY KEY,
 Name VARCHAR(50) NOT NULL,
 Vorname VARCHAR(50) NOT NULL);
 -- ------------------------
-CREATE TABLE Frauen 
+CREATE TABLE Frau
 (FrNr INTEGER NOT NULL PRIMARY KEY,
 Name VARCHAR(50) NOT NULL,
 Vorname VARCHAR(50) NOT NULL);
@@ -29,36 +27,36 @@ Vorname VARCHAR(50) NOT NULL);
 -- FOREIGN KEY Ehepaar_Frauen_FK (FrNr) REFERENCES Frauen (FrNr),
 -- PRIMARY KEY (MaNr, FrNr));
 -- ------------------------
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (1,'Jan', 'Müller');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (2,'Peter', 'Meier');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (3,'Jürgen', 'Sturm');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (4,'Jens', 'Stark');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (5,'Kurt', 'Schmitt');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (6,'Oswald', 'Peterson');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (7,'Thomas', 'Schneider');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (8,'Axel', 'Mertens');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (9,'Michael', 'Hoffmeister');
-INSERT INTO Männer (MaNr, Name, Vorname) 
+INSERT INTO Mann (MaNr, Name, Vorname)
 VALUES (10,'Jonas', 'Meerbad');
 -- ------------------------
-INSERT INTO Frauen (FrNr, Name, Vorname) 
+INSERT INTO Frau (FrNr, Name, Vorname)
 VALUES (11,'Julia', 'Bürkle');
-INSERT INTO Frauen (FrNr, Name, Vorname) 
+INSERT INTO Frau (FrNr, Name, Vorname)
 VALUES (22,'Iris', 'Mittermeier');
-INSERT INTO Frauen (FrNr, Name, Vorname) 
+INSERT INTO Frau (FrNr, Name, Vorname)
 VALUES (33,'Petra', 'Schnelle');
-INSERT INTO Frauen (FrNr, Name, Vorname) 
+INSERT INTO Frau (FrNr, Name, Vorname)
 VALUES (44,'Ruth', 'Stöhr');
-INSERT INTO Frauen (FrNr, Name, Vorname) 
+INSERT INTO Frau (FrNr, Name, Vorname)
 VALUES (55,'Michaela', 'Herb');
 -- ------------------------
 -- INSERT INTO Ehepaar (MaNr, FrNr) VALUES (1, 1); -- was bedeutet das?
@@ -72,8 +70,8 @@ VALUES (55,'Michaela', 'Herb');
 CREATE TABLE Ehepaar 
 (MaNr INTEGER NOT NULL,
 FrNr INTEGER NOT NULL,
-FOREIGN KEY Ehepaar_Männer_FK (MaNr) REFERENCES Männer (MaNr),
-FOREIGN KEY Ehepaar_Frauen_FK (FrNr) REFERENCES Frauen (FrNr),
+FOREIGN KEY Ehepaar_Männer_FK (MaNr) REFERENCES Mann (MaNr),
+FOREIGN KEY Ehepaar_Frauen_FK (FrNr) REFERENCES Frau (FrNr),
 PRIMARY KEY (MaNr, FrNr));
 -- --------------------------
 -- CREATE TABLE Ehepaar

Vorlesung/Übungen/Datenbanken5Übungen.sql

@@ -1,9 +1,9 @@
-USE 25_26;
 -- -----------------------------------------------
 -- Szenario: Relationale Algebra
 -- -----------------------------------------------
 
--- -----------------------------------------------
+USE 25_26;
+
 -- 1. Selection:
 SELECT Semester, Name FROM Student WHERE Semester = 1;
 
@@ -51,7 +51,7 @@ where v.Titel = 'Maßtheorie';
 SELECT * FROM Professor p LEFT OUTER JOIN Vorlesung v ON p.PersNr = v.gelesenVon;
 
 -- RIGHT OUTER JOIN:
-SELECT * FROM Professoren p RIGHT OUTER JOIN Vorlesung v ON p.PersNr = v.gelesenVon;
+-- SELECT * FROM Professoren p RIGHT OUTER JOIN Vorlesung v ON p.PersNr = v.gelesenVon;
 
 -- FULL OUTER JOIN (in MySQL mit 2 Joins)
 SELECT * FROM Professor p LEFT OUTER JOIN Vorlesung v ON p.PersNr = v.gelesenVon
@@ -78,13 +78,14 @@ insert into Senior (MatNr, Name, Semester, HSNr)
 values (103,'Paul', 1, 11);
 
 -- Natural Join
-SELECT * FROM Hochschulen NATURAL JOIN Senior;
+SELECT * FROM Hochschule NATURAL JOIN Senior;
 
 -- INTERSECTION (Schnittmenge)
-SELECT Name FROM Männer INTERSECT SELECT Name FROM Professoren;
+SELECT Name FROM Mann INTERSECT SELECT Name FROM Professoren;
 
 -- Gruppierung und Aggregatfunktion
 SELECT Semester as Semester, COUNT(*) as Anzahl FROM Student group by Semester;
+SELECT Semester as Semester, COUNT(*) as Anzahl FROM Student group by Semester;
 
 -- Sortierung
 SELECT * FROM Student order by Name;